(2+x)=2x^2-2x

Solution for (2+x)=2x^2-2x equation:

(2+x)=2x^2-2x

We move all terms to the left:

(2+x)-(2x^2-2x)=0

We add all the numbers together, and all the variables

(x+2)-(2x^2-2x)=0

We get rid of parentheses

-2x^2+x+2x+2=0

We add all the numbers together, and all the variables

-2x^2+3x+2=0

a = -2; b = 3; c = +2;
Δ = b2-4ac
Δ = 32-4·(-2)·2
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-5}{2*-2}=\frac{-8}{-4}
=+2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+5}{2*-2}=\frac{2}{-4}
=-1/2
$